I need help with Terms
@waterineyes
See, first of all where the LHS = RHS, that will give you infinite number of solutions..
For this, see 3..
ok?
In that, take 3 as common, and cancel it with denominator 3, what you will get?
1
\[\frac{3(x+1)}{3} =x+1 \\ x+1 = x+1\] This you will get.. Right?
yes
See, LHS is exactly same as right hand side, so now you put any value of x, you will get LHS = RHS..
Since here, you can put any value of x for which LHS = RHS, so it is having infinite number of solutions..
So is number 2. A and number 4. B? Then number 3 is C?
And so number 1 is A as well then because x = -14.2
All other are true except for 1.. 1 is not A, check it once again, how come you get \(x\) there as -14.2 ??
I'm not sure xD I'll redo my math.
\(2x -x = ??\)
Is 2x right?
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