Question

i need help with this 8^2x=11 solve the giver equation

Answer 1

what comes to mind, is taking log(base 8) of both sides.

Answer 2

\(\large \begin{align} \color{black}{
\normalsize \text{is it } \hspace{.33em}\\~\\
8^2x=11 \hspace{.33em}\\~\\
\normalsize \text{or} \hspace{.33em}\\~\\
8^{2x}=11 \hspace{.33em}\\~\\


}\end{align}\)

Answer 3

8^2x=11 so the secant one

Answer 4

u mean this one

\(\LARGE \begin{align} \color{black}{

8^{2x}=11 \hspace{.33em}\\~\\


}\end{align}\)

Answer 5

yes

Answer 6

OK

Answer 7

ya i don't under stand how to do it

Answer 8

\(\large \begin{align} \color{black}{

8^{2x}=11 \hspace{.33em}\\~\\

(8^{2})^x=11 \hspace{.33em}\\~\\
(64)^x=11 \hspace{.33em}\\~\\
\log (64)^x=\log 11 \hspace{.33em}\\~\\
x\log (64)=\log 11 \hspace{.33em}\\~\\
x=\dfrac{\log 11}{\log 64} \hspace{.33em}\\~\\
}\end{align}\)

see it makes sense

Answer 9

see if it makes sense

Answer 10

ok but it is not telling me what the ancer

Answer 11

2.0794 c. 2.3979
0.5766 d. 6.0902
it is one of them

Answer 12

that can be solved further by taking logs . so we have to take log for that.

Answer 13

ok

Answer 14

have they given log table ?

Answer 15

no

Answer 16

we can use the wolfram

http://www.wolframalpha.com/input/?i=%5Cdfrac%7B%5Clog+11%7D%7B%5Clog+64%7D%3D

Answer 17

ok

Answer 18

so its

\(\large \begin{align} \color{black}{

0.5766 \hspace{.33em}\\~\\
}\end{align}\)

Answer 19

\[\Huge \begin{array}l\color{red}{\text{w}}\color{orange}{\text{e}}\color{#E6E600}{\text{l}}\color{green}{\text{c}}\color{blue}{\text{o}}\color{purple}{\text{m}}\color{purple}{\text{e}}\color{red}{\text{ }}\color{orange}{\text{t}}\color{#E6E600}{\text{o}}\color{green}{\text{ }}\color{blue}{\text{o}}\color{purple}{\text{p}}\color{purple}{\text{e}}\color{red}{\text{n}}\color{orange}{\text{s}}\color{#E6E600}{\text{t}}\color{green}{\text{u}}\color{blue}{\text{d}}\color{purple}{\text{y}}\color{purple}{\text{
}}\color{red}{\text{}}\end{array} \]

Answer 20

ty so much