Complete the equation for the linear function whose graph contains the points (9, 7) and (4, –8). y − = (x − 9)
@Directrix
ok do u know d point slope formula?
no
\[(y-y1)=m(x-x1)\]
ok
\(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ 9}}\quad ,&{\color{blue}{ 7}})\quad &({\color{red}{ 4}}\quad ,&{\color{blue}{ -8}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}} \\ \quad \\ % point-slope intercept y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values}\\ \qquad \uparrow\\ \textit{point-slope form}\)
i got 1/5
your y1 is 7 and your x1 is already given as 9
all u need is look for d slope
got slope?
no
can i has it pleaseeeeeee
well.. that's the idea of the exercise, that you find it
so \(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ 9}}\quad ,&{\color{blue}{ 7}})\quad &({\color{red}{ 4}}\quad ,&{\color{blue}{ -8}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}} \\ \quad \\ % point-slope intercept y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values}\\ \qquad \uparrow\\ \textit{point-slope form}\) so..... what would that give you for "m" or the slope?
2/15
so simplify it for answer
ok what is ur y2 and y1?
-8 is my y2 my y1 is 7
ok subtract dem
i did i got -15
ok
what is ux2 and x1
sorry r x2
whatever u get subtract dem
k
-17
now divide -15/-17
i cant get the answer
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