how do you convert the function f(x)=15^x into a logarithmic one?
Do you mean, how do you solve for x?
think about this \[a^b=n \Longrightarrow \log_b(n)=a\]
so then you would get log(base)x(f(x))=15?
this one for natural log \[\ln x=y \Longrightarrow e^y=x\]
no use the equation \[y=15^x\]
eh it really doen't matter what you choose as a base and exponent
oh i made a mistake with the base lol
yes, that is what I was about to post...
I thought \(\large\color{black}{ \displaystyle a^b=n }\) \(\large\color{black}{ \displaystyle \log_aa^b=log_an }\) \(\large\color{black}{ \displaystyle b=log_an }\)
forgot the backwards slash next to logs, sorry for my bad latex.
again i wrote the same thing i must of drunk
\(\large\color{black}{ \displaystyle a^b=n }\) \(\large\color{black}{ \displaystyle \log_a(a^b)=\log_a(n) }\) \(\large\color{black}{ \displaystyle b\log_a(a)=\log_a(n) }\) \(\large\color{black}{ \displaystyle b=\log_a(n) }\)
It happens to me all the time, and I would bet more than to you.
yep it should be \[a^b=n \Longrightarrow \log_a(n)=b\]
does not happen to me usually lol just my brain is burned today hahah
so if we have \[y=15^x \Longrightarrow \log_{15}(y)=x\] just switch x and y and you get \[y=\log_{15}x\]
that is the function you are looking for
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