Question

How do you do this simple algebraic question?

Answer 1

\[\frac{ a^{2x}b ^{3x}(\sqrt{a^{3}})^x }{ b^{x-y}a}\]

Answer 2

Start with\[(\sqrt{a^3})^x\]\[(a^{\frac{3}{2}})^x\]\[a^{\frac{3}{2}x}\]

Answer 3

Gather the a's\[a^{2x}a^{\frac{3}{2}x}a^{-1}\]\[a^{\frac{4}{2}x}a^{\frac{3}{2}x}a^{-1}\]\[a^{\frac{7}{2}x-1}\]

Answer 4

\[a ^{\frac{ 7x-2 }{ 2 }}b^{2x-y}\]

Answer 5

Is that correct?

Answer 6

and the b's\[b^{3x}b^{-(x-y)}\]\[b^{3x-x+y}\]\[b^{2x+y}\]

Answer 7

haha darn. so close. don't know why I added the -1 for the a's.

Answer 8

I don't know? You asked how I would do it.

Answer 9

We're both right. I think.

Answer 10

Thanks man! You helped me. I forgot how to deal with the square roots.

Answer 11

\[a^{\frac{7}{2}x-1}b^{2x+y}\]

Answer 12

\[\sqrt{x}=x^{\frac12}\]

Answer 13

Thanks again. :)

Answer 14

I never use \(\sqrt\cdot\) I think they're ugly.