Hi I need help with ALgebra 2 problem! Can you just give me a sec to write down the equation that would be great!
\[3(x+3)^{3/4}= 81\]
I can try I'm in 7th grade. I'm in Algebra as well. :)
So these are my steps I will show okay give me one sec
okay thanks!
First I divided the 3 from both sides to get rid of that number. I got \[(x+3)^{3/4}=27\]
so then what I did was I did the opposite of the fraction sign.. and got \[\left| x+3 \right|=81\]
and then what I did was got this as my answer \[x+3= plus or minus 81\]
and then plugged 81 and -81 into x and got -78 and 84
but then i looked online for the answer that my techer put up and he had it without the absolute value sign but then that confused me with the rule you use
I have never done it that way before.....weird
Hm, Yeah.
yeah like it goes with this rule...but apparently I did it wrong but i followed the rules...
You needed to subtract 3 from both sides before you plug it in...
That is the only thing I can tell....
oh yeah... dude thanks!
Welcome ;)
I agree... If you don't mind may I ask for help with a question as well? Which of the following has a graph that is a straight line? Equation 1: y = 4x3 + 6 Equation 2: y = 5x − 4.5 Equation 3: y2 = x − 1 Equation 4: y = 2x2 + 6 I'm confused. :(
You might get more help if you post it in a new question ;)
.... girl it came out all funky I cant see a single thing.
yeah you should post a new one! Thanks guys!
Okay, Thank you anyways! ;)
your welcome!
thanks both of you!
:)
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