csc x(2sinx- sqrt 2) =0 Trigonometric function or not?
What is it that you're asking? \[\Large\rm \csc x\left(2\sin x-\sqrt2\right)=0\]Solve for x?
i need to figure out if it's a trigonometric identity or not
I didn't mean function, sorry :x
Are you sure you read the directions correctly? 0_o This sure looks like a "solve for x" problem. Hmm
yeah, it says "decide whether the equation is a trigonometric identity"
\(\Large\rm \csc x\) is equivalent to \(\Large\rm \dfrac{1}{\sin x}\). So that gives us\[\Large\rm \frac{1}{\sin x}\left(2\sin x-\sqrt2\right)=0\]Distributing that to the bracketed stuff gives us,\[\Large\rm 2-\frac{\sqrt2}{\sin x}=0\]When we're trying to verify whether or not something is an identity, we only alter one side and try to make it match the other side.
So in this case, yes there are specific x values which will give us 0 on the left side, making this true, but it is certainly not an identity. >.<
Weird stuff :U
yeah, it is. Thank you a lot, though. That makes sense C:
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