Help?? :/
A 1150 Kg wrecking ball is lifted to a height 13.0 meters above its resting point. What is the potential energy of the wrecking ball at this height?
146510 J
14950 J
127.4 J
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OpenStudy (perl):
potential energy = mass * height * gravity constant
OpenStudy (anonymous):
So then would it be B: 14950 J?
OpenStudy (perl):
1150 kg * 13 meters * 9.8 meter/s^2 =
OpenStudy (anonymous):
Ohhh ok. So it'd actually be A?
OpenStudy (haichi):
41 veiwing
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OpenStudy (anonymous):
I know, what the heck is that about??
OpenStudy (haichi):
idk?
OpenStudy (haichi):
@perl
OpenStudy (anonymous):
ahahah
OpenStudy (anonymous):
Potential energy is mgh
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OpenStudy (haichi):
XD
OpenStudy (anonymous):
\[U = mgh\]
OpenStudy (anonymous):
Just realized perl said it earlier
OpenStudy (anonymous):
So.. its 146510 J?
OpenStudy (anonymous):
Looks good
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OpenStudy (perl):
Joules has units of kg m^2/s^2 , and your solution does :)
OpenStudy (anonymous):
Yay! Thank you!! Mind helping with another one? Whats the formula for Kinetic Energy? Its the same question, I just have to find KE.
OpenStudy (anonymous):
\[K = 1/2 mv^2\]
OpenStudy (anonymous):
Hm. I keep getting 97175...
OpenStudy (anonymous):
who what where when why how
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OpenStudy (anonymous):
I took v^2 which i assumed was 13^2 and i multiplied 0.5 * 1150 * 169 and got 97175
OpenStudy (anonymous):
v = velocity, why would the height be the velocity, which is measured in m/s :P
OpenStudy (anonymous):
Oh thats right. I got ahead of myself. Ok let me re-work that... Ugh. im just gonna take a guess. Is it 14950 J?
OpenStudy (anonymous):
You're given the same options for KE?
OpenStudy (anonymous):
Yes.
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OpenStudy (anonymous):
Alright, ever heard of conservation of energy?
OpenStudy (anonymous):
Yes. Dont know too much about it tho...
OpenStudy (anonymous):
PE = mgh
OpenStudy (anonymous):
You can set the equations equal to each other and solve for v and then plug back into KE and solve for KE
OpenStudy (anonymous):
You'll get an interesting answer, that will follow conservation of energy!