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Mathematics 7 Online
OpenStudy (anonymous):

Help?? :/ A 1150 Kg wrecking ball is lifted to a height 13.0 meters above its resting point. What is the potential energy of the wrecking ball at this height? 146510 J 14950 J 127.4 J

OpenStudy (perl):

potential energy = mass * height * gravity constant

OpenStudy (anonymous):

So then would it be B: 14950 J?

OpenStudy (perl):

1150 kg * 13 meters * 9.8 meter/s^2 =

OpenStudy (anonymous):

Ohhh ok. So it'd actually be A?

OpenStudy (haichi):

41 veiwing

OpenStudy (anonymous):

I know, what the heck is that about??

OpenStudy (haichi):

idk?

OpenStudy (haichi):

@perl

OpenStudy (anonymous):

ahahah

OpenStudy (anonymous):

Potential energy is mgh

OpenStudy (haichi):

XD

OpenStudy (anonymous):

\[U = mgh\]

OpenStudy (anonymous):

Just realized perl said it earlier

OpenStudy (anonymous):

So.. its 146510 J?

OpenStudy (anonymous):

Looks good

OpenStudy (perl):

Joules has units of kg m^2/s^2 , and your solution does :)

OpenStudy (anonymous):

Yay! Thank you!! Mind helping with another one? Whats the formula for Kinetic Energy? Its the same question, I just have to find KE.

OpenStudy (anonymous):

\[K = 1/2 mv^2\]

OpenStudy (anonymous):

Hm. I keep getting 97175...

OpenStudy (anonymous):

who what where when why how

OpenStudy (anonymous):

I took v^2 which i assumed was 13^2 and i multiplied 0.5 * 1150 * 169 and got 97175

OpenStudy (anonymous):

v = velocity, why would the height be the velocity, which is measured in m/s :P

OpenStudy (anonymous):

Oh thats right. I got ahead of myself. Ok let me re-work that... Ugh. im just gonna take a guess. Is it 14950 J?

OpenStudy (anonymous):

You're given the same options for KE?

OpenStudy (anonymous):

Yes.

OpenStudy (anonymous):

Alright, ever heard of conservation of energy?

OpenStudy (anonymous):

Yes. Dont know too much about it tho...

OpenStudy (anonymous):

PE = mgh

OpenStudy (anonymous):

You can set the equations equal to each other and solve for v and then plug back into KE and solve for KE

OpenStudy (anonymous):

You'll get an interesting answer, that will follow conservation of energy!

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