Question

What is the equation in standard form of the line which passes through (4, - 2) and has a slope of -3?

Answer 1

@Nurali

Answer 2

@sleepyjess

Answer 3

I am thinking we should first get point slope form then convert that to standard form.

Answer 4

So point slope form would be y + 2 = -3(x - 4)

Answer 5

ok... -3 * x = -3x and -3 * 4 = -12

so y + 2 = -3x - 12 ?

Answer 6

Yep, then we need to get y to the right side.

Answer 7

add 3 ?

Answer 8

We use the formula:

y - y1 = m(x - x1)
y - (-2) = -3(x - 4)
y - (-2) = y + 2
Now we have:
y + 2 = -3(x - 4)
Cross multiply:
(y + 2) = -3(x - 4)
Therefore:
y + 2 = -3x +12
y=-3x+12-2
y=-3x+10

Answer 9

We could also add 3x. I think that is what you were trying to say?

Answer 10

That is slope-intercept form though...

Answer 11

wait what

Answer 12

@Nurali did slope-intercept form. They are asking for standard form which is c = ax + by

Answer 13

oh ok.. so 3x + y + 2 = -12

Answer 14

Yeah, that works :) now just subtract 2 and we're done ^_^

Answer 15

3x + y = -14

Answer 16

Wait, it should be +12

Answer 17

o-o ohh

Answer 18

-3*-4 = 12

Answer 19

3x+y=10

Answer 20

ohhhhhhhhh 3x + y = 10... mkay cx

Answer 21

thanks

Answer 22

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