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Chemistry 16 Online
OpenStudy (anonymous):

How Do You Know What Ratio Your Equation Is @jordanloveangel

OpenStudy (jordanloveangel):

hold on

OpenStudy (anonymous):

Okay

OpenStudy (jordanloveangel):

can i see the problem?

OpenStudy (anonymous):

Potassium permanganate (KMnO4) reacts with hydrochloric acid (HCl) to form potassium chloride (KCl), manganese chloride (MnCl2), water (H2O), and chlorine gas (Cl2). The balanced chemical equation is 2KMnO4 + 16HCl → 2KCl + 2MnCl2 + 8H2O + 5Cl2. Select the correct ratios of each of the following substances. KMnO4:KCl = HCl:H2O = KMnO4:Cl2 = HCl:MnCl2 =

OpenStudy (jordanloveangel):

OpenStudy (anonymous):

So I Use The Molar Mass ?

OpenStudy (jordanloveangel):

OpenStudy (jordanloveangel):

i think so

OpenStudy (anonymous):

I Multiply It By ?

OpenStudy (aaronq):

The ratios come from the stoichiometric coefficients in the balanced equation 2 KMnO4 + 16 HCl → 2 KCl + 2 MnCl2 + 8 H2O + 5 Cl2 ^ ^ ^ ^ ^ ^ i'll do the first KMnO4:KCl = 2:2 HCl:H2O = KMnO4:Cl2 = HCl:MnCl2 =

OpenStudy (anonymous):

So The Second One Is 2:1 ?

OpenStudy (aaronq):

16:8 -> 2:1 yes!

OpenStudy (anonymous):

Ahaa Ayee I Got It ! :D

OpenStudy (aaronq):

sweeet

OpenStudy (anonymous):

In the reaction N2 + 3H2 mc016-1.jpg 2NH3, how many moles of hydrogen are needed to produce 7.61 mol of ammonia? (Answer should be precise to the nearest 0.1 mol.) ???

OpenStudy (aaronq):

so it builds on the previous concept of molar ratios. you use the moles and stoichiometric coefficients of what you're interested in, in this case it looks like: \(\sf \dfrac{moles~of~H_2}{H_2's~coefficient}=\dfrac{moles~of~ammonia}{ammonia's~coefficient}\)

OpenStudy (anonymous):

3.9 mols ?

OpenStudy (aaronq):

how did you set that up?

OpenStudy (anonymous):

I Tried To Do It Like That But I Dont Think I Did It Right /.\

OpenStudy (aaronq):

show me what you did and i'll correct it

OpenStudy (anonymous):

|dw:1423855719912:dw|

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