Help with true and false questions about cosecant and secant functions
1.The vertical asymptotes of the cosecant function are located at the same values of x for which the sine function is equal to 0. 2.The vertical asymptotes of the secant function are located at the same values of x for which the sine function is equal to 0.
secant=1/cosine so when cosine is 0 secant is undefined right?
Yeh I just saw this in my notes so it would be the secant that is true and false for cosecant?
@freckles
wait which are you saying is true?
1 or 2?
so im saying 1 is false and 2 is true
why would you say 2 is true when I just said that secant=1/cosine and when cosine is 0 secant is undefined?
also we will look at 1 again after we have finished looking at 2
I miss thought is all then s: see I just got done dealing with Cotangent and if Cos=0 that means that it would be true but we arent dealing with that
\[\sec(x)=\frac{1}{\cos(x)} \\ \text{ if } \cos(x)=0 \text{ then } \sec(x)=\frac{1}{0} \\ \text{ you cannot divide by 0 }\]
Yes that is true you cannot
so that means sec(x) has a vertical asymptote when cos(x) is 0
so number 2 is true or false?
I am confused s: if cos is 0 that means it is undefined
exactly
so how does that work?
So if it is undefined it has vertical asymptotes?
oh wait
usually 0/0 means you have a hole but if you have a/0 where a isn't 0 then you definitely have a vertical asymptote Remember f(x)=1/x That function looks like: |dw:1423859101794:dw| 1/x is undefined when x=0 so since we have 1/0 we definitely have a vertical asymptote at x=0
2 is false because it says sine not cosine
right if sin=0 then cos is definitely not zero at the same time
now what about number 1?
Yes this is true aha sorry
I would say that it\[\cos(x)=\frac{ 1 }{ \sec(x) }\]
1.The vertical asymptotes of the cosecant function are located at the same values of x for which the sine function is equal to 0. remember cosecant=csc csc(x)=1/sin(x) correct?
Omg
*FACEPALMS*
I was like cosecant must be COS *FACEPALMS*
cosine=cos sine=sin cosecant=csc secant=sec cotangent=cot tangent=tan
Yes yes I failed sorry my mind just went all stupid mode lool
lol anyways this is basically the same question before except with a different story ending
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