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Mathematics 7 Online
OpenStudy (nepurrta):

Help I don't understand what this is asking for? For the Function f(x)=10x^2+x, evaluate and simplify the expression (f(a+h)-f(a))/h.

OpenStudy (kainui):

Can you evaluate f(2) if you needed to?

OpenStudy (nepurrta):

If f(2) is f(x) then yes but I don't understand where it's getting a and h from and how f(x) goes into that.

OpenStudy (nepurrta):

Like f(2) replace the x's with 2's in 10x^2+x, but where does a and h come in to the problem?

OpenStudy (kainui):

Yeah, you have the exact right idea, the reason I ask is because there's really no difference between evaluating f(2) as there is evaluating f(a+h). Only difference is you're plugging in (a+h) instead of 2. Try it out.

OpenStudy (nepurrta):

Ooooh. So instead of 10(2)^2+2 it'd be 10(a+h)^3+(a+h)?

OpenStudy (nepurrta):

^2* not ^3

OpenStudy (kainui):

Yeah, exactly =)

OpenStudy (nepurrta):

Thanks. I was really confused xD

OpenStudy (kainui):

Yeah no problem, want me to check your final answer for you?

OpenStudy (nepurrta):

I'm still trying to simplify it into one of the options. Not as easy at it sounds :c

OpenStudy (nepurrta):

I keep getting stuck at (-10 a^2+10 (a+h)^3+h)/h which is not an option

OpenStudy (kainui):

You have to distribute (a+h)^2 are you familiar with that, sometimes they call it FOIL

OpenStudy (nepurrta):

I haven't heard of FOIL in years - so I don't really remember it. Sorry :c

OpenStudy (kainui):

Well really all you need to know is how to multiply binomials together (a+h)^2 is just (a+h)*(a+h). Unfortunately I gotta go, but maybe you can find something about it on the internet if not someone else here.

OpenStudy (nepurrta):

Okay well thanks for the help c:

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