Question

What is the simplified form of \[\frac{ 1 }{ x }-\frac{ 2 }{ x^2-x }\]

Answer 1

I think its \[\frac{ x-3 }{ x(x-1) }\] Because 1-2 is -3. Then x times x is x^2. Then x times -1 is -x.

Answer 2

I'm not completely sure.

Answer 3

correct.

Answer 4

:o Really?

Answer 5

\[
\frac{1}{x} - \frac{2}{x^2-x} = \frac{1}{x} - \frac{2}{x(x-1)} =
\frac{1}{x}*\frac{x-1}{x-1} - \frac{2}{x(x-1)} = \\
\frac{x-1}{x(x-1)} - \frac{2}{x(x-1)} = \frac{x-1-2}{x(x-1)} = \frac{x-3}{x(x-1)}
\]

Answer 6

Wow thank you!

Answer 7

you are welcome.

Answer 8

dot.