Question

What is the simplified form of \[\frac{ x+4 }{ x^2+x-12 }\times \frac{ x+4 }{ x^2+8x+16 }\] ?

Answer 1

Can you factor the denominators? If you factored them, you can get some cancelings..

Answer 2

That's what I need help with. Factoring them out.

Answer 3

\[\frac{ 1 }{ (x+3)(x-4) }\] \[\frac{ 1 }{ (x-4)^2 }\] \[\frac{ 1 }{ (x+4)^2 }\] \[\frac{ 1 }{ (x-3)(x+4) }\]

Answer 4

that is for left side bottom one ??
which is x^2 + x -12

Answer 5

Yes.

Answer 6

okay so for that easy method is to find two number if you add them you should get middle number which is 1
and if you multiply that two numbers you should get -12
so -4 times 3 = ??
-4+ 3 = ?

Answer 7

-12
-1

Answer 8

@Zale101 look it there she is back!!

Answer 9

yes -4 +3 = -1 but you should have positive one so play with number and see how you get positive one

Answer 10

With any number?

Answer 11

you can factor -12

Answer 12

you have -4 and 3 which is almost right
play with signs and see if you get positive one

Answer 13

4+(-3)=1

Answer 14

yes that's right
because your leading coefficient is one so you can just right it as (x +4) and (x-3)

Answer 15

Ohh okay.

Answer 16

now factor right bottom side
again because your leading coefficient is 1 so you can just find two number if you multiply them you should get positive 16 and if you add or subtract them you should get positive 8

Answer 17

Two same numbers to get 16 or any?

Answer 18

some times it can be same
but not always

Answer 19

Okay.

Answer 20

okay lets do it this way
factor 16
and factor x^2