Question

Based on the information shown below, how many grams of ammonium perchlorate, NH4ClO4, can be formed from these reactants in an excess of water?
Gas Density (g/L) Initial Volume (L)
NH3 0.759 2.00
HCl 1.63 1.00

NH3(g) + HCl(g) + 4H2O(l) NH4ClO4(s) + 4H2(g)

A. 5.25 g
B. 3.22 g
C. 1.52 g
D. 1.63 g

Answer 1

@Zale101

Answer 2

NH3(g) + HCl(g) + 4H2O(l) ---> NH4ClO4(s) + 4H2(g)

Answer 3

It's D right?

Answer 4

Can i see how you worked the problem.

Answer 5

@Jesstho.-.

Answer 6

@ganeshie8

Answer 7

@Zale101 Am I right? Is it D?

Answer 8

I dont understand how is it possible to get the mass if you have only density and initial volume.
\(Density=\Large \frac{Mass}{total~ volume-initial~ volume}\)
Mass=Density*Volume
\(Mass=Denisty*(total~ volume-initial~ volume)\)
In this case, we have only initial volume given.

Answer 9

Can you show us what you did here? You're not giving us much to work with.