Given f ′(x) = (5 – x)(8 – x), determine the intervals on which f(x) is increasing or decreasing. a)Decreasing (–∞, 5); increasing on (8, ∞) b)Increasing (–∞, –5) U (–8, ∞); increasing on (–5, –8) c)Decreasing (5, 8); increasing on (–∞, 5) U (8, ∞) d)Decreasing (–∞, 5) U (8, ∞); increasing on (5, 8)
Please try to solve the inequality below: \[\left( {5 - x} \right)\left( {8 - x} \right) \geqslant 0\]
do you want me to factor it out to get: 40-5x-8x+x^2 40-13x+x^2
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for example, try to solve this: 5-x >=0
oh so x= -5 and x = -8
no, those are the roots, you have to find the solution of the inequality (5-x)(8-x)>=0, instead
i dont see where the > comes in place with the = sign
here i'll give it a shot: 5-x>=0 -x>=-5 x>=5
there is a theorem which states this: " a function f(x) is an increasing function if and only if f '(x) >=0" So you have to apply that theorem
do you mean greater than or equal to 0?
yes!
the last step is incorrect since if you multiply an inequality by a negative quantity, then that inequality change its direction, so if we have -x >= -5 then x <= 5
ohhh i thought you had them as 2 separate things, perfect :) yes im sorry i forgot that rule so i dont see how it relates to the answer
it is simple, please solve this another inequality: 8-x >=0
x<=8
i think i figured it out! is it C? :)
that's right so, we have this subsequent drawing:
wait please!
c)Decreasing (5, 8); increasing on (–∞, 5) U (8, ∞)
|dw:1423948543408:dw|
do you unerstand that diagram?
yes it is increasing
oops...understand...
on (5,8)
that diagram tell us that when x<=5 both quantities namely (5-x) and (8-x) are positive, so their product is also positive
got it
now please look at this diagram:
|dw:1423948739597:dw|
that diagram tell usthat whe x is grether than 8 both quantities, namely (5-x) and (8-x) are neative, nevertheless their product is stil positive.
oops ...are negative...
its okay :) with that being said, i think its b because positive means increase correct?
please wait our conclusion is that the function f'(x) is positive when x <5 and x >8 so applying the theorem above, our function f(x) is an icreasing function when x<5 and x>8
yes! first derivative positive, means increasig function
okay so is it b? :) b)Increasing (–∞, –5) U (–8, ∞); increasing on (–5, –8)
I think that ur function is an incresing function in \[\left( { - \infty ,5} \right) \cup \left( {8, + \infty } \right)\]
ohh true cause it would be the opposite decreasing on both positive 5 & 8 (5,8) :) THANKU!!
thank you!!
U r an amazing teacher!!!! :D
thank! again!
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