Choose the equation below that represents the line passing through the point (-2, -3) with a slope of -6.
y + 3 = -6(x + 2)
y + 2 = 6(x + 3)
y - 3 = -6(x - 2)
y - 2 = 6(x - 3)
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OpenStudy (anonymous):
@Nnesha
OpenStudy (anonymous):
yoooooo
Nnesha (nnesha):
y = mx +b slope intercept form
where m is slope so replace m by -6
OpenStudy (ribhu):
y-y1 = m(x-x1)
OpenStudy (anonymous):
hi @iambatman
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OpenStudy (anonymous):
ok @Nnesha
OpenStudy (anonymous):
this is point slope form, so you coordinates are (x1,y1) just use the equation ribhu showed you, and slope is m.
OpenStudy (ribhu):
now x1,y1 is the point from which the line passes and slope of line is m.
OpenStudy (ribhu):
@heymydearpeople try to do on your own using this concept.
OpenStudy (anonymous):
@Nnesha
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OpenStudy (ribhu):
its not slope intercept form @Nnesha
Nnesha (nnesha):
yes ??
OpenStudy (anonymous):
which form is correct?
Nnesha (nnesha):
your answer are in point slope form so use that one
OpenStudy (anonymous):
the one that @iambatman said
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OpenStudy (anonymous):
and @ribhu
Nnesha (nnesha):
yes
OpenStudy (anonymous):
\[y-y _{1}=m(x-x _{1}) \]
OpenStudy (anonymous):
here is the part that always confuses me whatt do i plug in @Nnesha @iambatman
Nnesha (nnesha):
(x . y ) replace x1 and y1
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OpenStudy (anonymous):
You have the points (-2, -3) this is your (x1,y1) and your slope is the m in the equation which is -6.
OpenStudy (anonymous):
what is x and y
OpenStudy (anonymous):
You leave that alone
OpenStudy (anonymous):
? @iambatman
OpenStudy (anonymous):
You don't plug anything in the y and x, just y_1 and x_1 even look at your choices.
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