The graph below plots a function f(x):
graph of line segment going through ordered pairs 0, 100 and 3, 220
If x represent time, the average rate of change of the function f(x) in the first three seconds is ___.
Numerical Answers Expected!
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OpenStudy (anonymous):
@iambatman
OpenStudy (anonymous):
Average rate of change it just the slope
OpenStudy (anonymous):
\[\huge m=\frac{ y_2-y_1 }{ x_2-x_1 }\]
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
Your ordered pairs are (0,100) and (3,220) just plug and chug
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OpenStudy (anonymous):
?
OpenStudy (anonymous):
You have to tell me what part you don't understand giving me a question mark won't help.
OpenStudy (anonymous):
The points you're given
OpenStudy (anonymous):
@iambatman i do not understand who to plyg and chug xd
OpenStudy (anonymous):
(0,100) and (3,220)
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OpenStudy (anonymous):
where do plug those into the equation though
OpenStudy (anonymous):
The first coordinate is (x1,y1) and the other is (x2,y2)
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
x1=0 y1,= 100 x2=3 y2=220 @iambatman like that?
OpenStudy (anonymous):
Yeah, now use the slope formula
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OpenStudy (anonymous):
The slope formula is what I wrote above, did you get it?
OpenStudy (anonymous):
no @iambatman
OpenStudy (anonymous):
Well show me an attempt and I'll tell you if you're right or not
OpenStudy (anonymous):
m=2202-1001/32-01 @iambatman
OpenStudy (anonymous):
2202? 1001?
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OpenStudy (anonymous):
\[m=\frac{ 220-100 }{ 3-0 }\]
OpenStudy (anonymous):
yes @iambatman
OpenStudy (anonymous):
@iambatman
OpenStudy (anonymous):
220-100/3 =?
OpenStudy (anonymous):
33.333333333... @iambatman
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