Which function's domain consists of all real numbers except 3? a) f(x)=3x+3 b) f(x)=3/x-3 c) f(x)=3x^2 d) f(x)=3x-3 e) f(x)= 1/ square root of x-3
Look at the ones like f(x) = 3/(x-3) is it in brackets? If so, what makes the function undefined/ zero?
it's f(x)=3/x-3 , it's not in brackets.
well i mean is it |dw:1423974882433:dw|
the second one
Yeah, so what happens if you plug in 3?
so are you saying the answer is B?
No, I'm asking you a question, what happens when you plug 3 for x?
The math question is like that, idk how to solve it.
Domain is the x values, so can you plug every number in this questions and get a solution? It's restricted if you have an undefined or it equals 0.
So you have f(3) = 3/(3-3) = 3/0 so this can't be all real numbers.
So what do you suggest is the answer?
You're looking for the functions that are undefined at x = 3.
So plug in x in the functions you're given and see if it's undefined, when you divide by 0 you get undefined.
do you understand?
You cannot have 0/x or x/0.
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