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State the limits of the following sequences, or state that the limit does not exist 5, 6 1/2, 5 2/3, 6 1/4, 5 4/5, 6 1/6,..., 6+(-1)^n/n.. Can anyone explain why that the answer is \[\lim_{n \rightarrow \infty}6+(-1)^n/n = 6\]?
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HI!!
the larger \(n\) gets the close \(\frac{(-1)^n}{n}\) gets to zero
So it means \[\lim_{n \rightarrow \infty} 6+(0) = 6?\]
\[\lim_{n \rightarrow \infty} 6+\frac{(-1)^n}{n}\] \[=6+\lim_{n\to \infty}\frac{(-1)^n}{n}=6+0=6\]
okay thanks!
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