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Chapter 5:Indices and Logarithms @ganeshie8
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\[Given~that~3^{2x}-1-7=0,\]find the value of x by giving the answer correct to 2 decimal places.
\[3^{2x}=8\]
take the natural logarithm of both sides
\[\log _{10}3^{2x}=\log _{10}8\]
Yes, that works to, 2x comes down
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\[2xlog _{10}3=\log _{10}8\]
yeah
\[2x=\frac{ \log _{10}8 }{ \log _{10}3 }\]
Yup, finish it off
\[x=0.95\]
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Thnx @iambatman :)
Np
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