Solve the following Absolute Value Equation. (see comments)
\[\left| 6-4x \right|=\left| 2x-1 \right|\]
\(\huge\color{rde}{WELCOME~TO~OPENSTUDY!!!}\)
we also have to graph it and write the interval notation for it. the teacher hasn't shown us how to do this type yet. just \[>,\le,\ge,<,\]
square both the sides to remove modulus functions. @jpes2193
so i got the solution set {7/6, 5/2} but how would I graph it ?
Alrighty, mate. For simplicity's sake |A| = |B| So now, when we remove the modulus, we have two cases for each equation on LHS and RHS - as it is, or with a 'negative' sign next to the entire equation. Hence, we have 2 options: A = B -A = B -A = -B A = -B Since, the last two options mean the same as the first 2, respectively, we can eliminate them, and consider only the first two. then solve.
plot the modulus function graphs.
|dw:1424023598049:dw|
the graphs are not to scale but the basic pattern of the graphs would be the same.
See, for the above noted values of X, the equation, y = |6-4x|-|2x-1| becomes zero. Hence, the two straight lines formed by A and B would mirror from these two points. An example:|dw:1424023664321:dw|
@jpes2193 you can graph it like that
Also, you must have realised the curve never travels below the y=0 line, i.e. X-axis, because, difference of 2 mods, |A| - |B| can NOT be negative.
@apoorvk it would be quite confusing for her. i think i have simplified it nicely what do u say?
Yeah, you can follow Ribhu, his explanation is pretty spot on too. Try visualising.
|dw:1424023834199:dw|
thanks @apoorvk
@jpes2193 this solves ur graph problem.
@jpes2193 you got this question.
Thanks so Much!!!
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