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Mathematics 16 Online
OpenStudy (anonymous):

If f(x) = arcsin(2x), then f '(x) = ? *answer choices attached in pic file below* i chose A, :)

OpenStudy (anonymous):

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

yes so it's sin-1(2x)

OpenStudy (jhannybean):

Oh crap, ireadit as arctan.

OpenStudy (jhannybean):

My bad x.x

OpenStudy (anonymous):

Its okay, you described the concept good :)

OpenStudy (jhannybean):

Sorry about that.

OpenStudy (anonymous):

its okay :))

OpenStudy (anonymous):

arcsinx derivative is \[\frac{ 1 }{ \sqrt{1-x^2} }\]

OpenStudy (jhannybean):

\[\frac{d}{dx}( \sin^{-1}(x)) = \frac{1}{\sqrt{1-x^2}}\]

OpenStudy (anonymous):

Once again, chain rule here :P

OpenStudy (jhannybean):

And your x in this case is 2x, ^^

OpenStudy (jhannybean):

Batman beat me toit.

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