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If f(x) = arcsin(2x), then f '(x) = ? *answer choices attached in pic file below* i chose A, :)
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@ganeshie8
yes so it's sin-1(2x)
Oh crap, ireadit as arctan.
My bad x.x
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Its okay, you described the concept good :)
Sorry about that.
its okay :))
arcsinx derivative is \[\frac{ 1 }{ \sqrt{1-x^2} }\]
\[\frac{d}{dx}( \sin^{-1}(x)) = \frac{1}{\sqrt{1-x^2}}\]
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Once again, chain rule here :P
And your x in this case is 2x, ^^
Batman beat me toit.
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