What are the possible numbers of positive, negative, and complex zeros of f(x) = -3x^4 + 5x^3 - x^2 + 8x + 4?
@satellite73
fractions where the numerator divides 4 and the denominator divides 3
there are a few of those
the 8x and 4?
divisors of 4 are \[\pm1,\pm2,\pm4\] so do the same with a 3 in the denominator
ignore everything but the 4 at the end and the 3 at the beginning
k so since you already found the 4 all i gotta do is the -3x^4?
the others are \[\pm\frac{1}{3}\] and so on
do you want to see the answer choices?
no
i don't know how to do this im not sure what you mean by 3 as the denominator like do you want any fraction with 3 as the denominator ?
\[\pm \frac{1}{3},\pm \frac{2}{3},\pm\frac{4}{3}\]
got it?
yeah so like [\pm\frac{ 6 }{ 3 }\] would that work?
\[\pm \frac{ 6 }{ 3 }\]
lol just the ones i wrote the top as to divide 4
okay so i devide all those by 4 or what?
let me write them out for you ok?
ok
\[\pm1,\pm2,\pm4\pm \frac{1}{3},\pm \frac{2}{3},\pm\frac{4}{3}\]
top goes in to 4, bottom goes in to 3
ohhh i see what you mean like the numerator goes into 4 and he denominator goes into 3?
yay
but thats not one of the answer choices
oooh i see
crap we have to use descartes rule of sign
\[ f(x) = -3x^4 + 5x^3 - x^2 + 8x + 4\] has 3 changes in sign from -3 to +5, from +5 to -1, from -1 to +8
so there are either 3 positive zeros, or one positive zero (you count down by twos)
\[f(-x) = -3x^4 - 5x^3 - x^2 - 8x + 4\] has one change in sign from -8 to +4
i thought 0 was a nutreul number? not negative nor positive?
changes in sign of the coefficients yes, zero is not negative or positive, we are counting the roots
oh okay
Positive: 2 or 0; negative: 2 or 0; complex: 4 or 2 or 0 Positive: 1; negative: 3 or 1; complex: 2 or 0 Positive: 3 or 1; negative: 1; complex: 2 or 0 <--- s this the answeR? Positive: 4 or 2 or 0; negative: 2 or 0; complex: 4 or 2 or 0
well we don't have to do much work because only one choice starts with positive zeros 3 or 1
yeah C as you picked
thank you i got a whole bunch more btw Xd
Join our real-time social learning platform and learn together with your friends!