Question

Quick question, can someone tell me the equation of this graph below

Answer 1

I mean the function***

Answer 2

This is a parabola. What is the vertex in this case?

Answer 3

(-2, 2) ?

Answer 4

that is correct

Answer 5

in general, the vertex is (h,k)

Answer 6

so (h,k) = (-2,2) which means h = -2 and k = 2

Answer 7

vertex form in general is y = a(x-h)^2 + k. Hopefully that looks familiar?

Answer 8

yes, it does :)

Answer 9

Plug in (h,k) = (-2,2)

y = a(x-h)^2 + k

y = a(x-(-2))^2 + 2

y = a(x+2)^2 + 2

now you plug in another point that lies on the parabola that isn't the vertex. Another point I see that lies on the parabola is (-1,1). So plug in (x,y) = (-1,1)

y = a(x+2)^2 + 2

1 = a(-1+2)^2 + 2

I'll let you finish and solve for 'a'. Tell me what you get.

Answer 10

ok hold on :D

Answer 11

a= 1?

Answer 12

close

Answer 13

but not quite

Answer 14

i mean -1

Answer 15

yep, a = -1

Answer 16

yayy

Answer 17

so y = a(x+2)^2 + 2 turns into y = -1(x+2)^2 + 2 which is the same as y = -(x+2)^2 + 2

Answer 18

thank you so very very much!

Answer 19

np

Answer 20

hey jim can you help me find the axis of symmetry using this @jim_thompson5910

Answer 21

actually nevermind I got it :)

Answer 22

I'm glad you figured it out