Does the probability of rolling a sum of 2 appear to be the same as the probability of rolling a sum of 7? Explain your answer.
Empirical or theoretical probability?
I have seen your question yesterday and If I remember correctly the question was referring to empirical probability It was basically based on your observations
You had to roll the die 60 times and then record the amount of times it landed on each number
yes but this question is different im having trouble with probablity
ok well then lets pretend or assume that this is theoretical probability Ok when you roll a die once there are a total of 6 diff options - it can land on any of 6 number. It can land on 1 , 2, 3, 4, 5, and 6 The probability that it will land on 1 is ... \[ \text{ Probability of 2} = \frac{\text{ How many times it lands on 2}}{\text{ Total # of outcomes}}\] Now lets look above ... How many outcomes are there??? 6 . It can land on 6 numbers ... 1,2,3,4,5 and 6 How many times does it land on a 2??? Only once so 1 Therefore the probability that it will land on 2 is \[ \text{ Probability of 2} = \frac{\text{ 1}}{\text{ 6}}\]
Oh whoopppsssss Didnt read the question ... it asks for sum of 2 and sum of 7
ok this all depends on how many times you roll a die
Is there more to the question?
well i have more questions
ya but is there a first part to the question?
Like im assuming that you havta roll the die twice
so for example there is not a single answer? your answer will be differfent then mine depending on how many times i roll the dice?
no thats the whole question
Not really ... thats only in empirical probability
In theoretical probability its always the same its always a 1/6 that you will land on a 2
ok so lets see when you roll the die twice The only way you can get a sum of 2 is if you roll a 1 on the first time and a 1 on the second time you roll the die 1+1=2
So the probability that you will get a 1 is a 1/6 so (1/6)*(1/6)=1/36 The probability that you will roll on 1 twice in a row is 1/36
for a sum of 7 you can need to roll on a 3 and 4 so its 3+4=7 Now there are 2 ways to get a sum of 7 and I will show you below Option#1 Roll #1 we get 3 Roll #2 we get 4 Probability that will land on 3 is a 1/6 Probability that will land on 4 is a 1/6 So probability that will first land on 3 and then 4 is (1/6)*(1/6)=1/36 Option#2 Roll #1 we get 4 Roll #2 we get 3 Probability that we will land on 4 is 1/36 Probability that will land on 3 is 1/6 Probability that will land on both is (1/6)(1/6)=1/36 The probability that we will get either option 1 or option 2 is (1/36)+(1/36)=2/36 So therefore the probability that will get a sum of 7 is 2/36
So does the probability appear to be the same?????
Ok i dont think i explained this clearly ...
yes
hmmm i gotta go study but maybe @freckles would like to help :P
So how many dice do you have? 2,3,4,5? I assumed it was more than 1 since you said sum of the die.
If it is 2 die: |dw:1424052026764:dw| This picture represents all the possible outcomes of rolling two fair die together
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