Question

A net force of 12.0N north acts on a object for 2.00*10^-3 . calculate the impluse

Answer 1

@Abhisar

Answer 2

hello there..impulse is that force which is applied on to an object for a very short period of time
it is given by J = F * dt
where F is the force and dt is the small time interval
now F= 12N
dt=2*10^-3
calculate J by substituting these values :)
and its unit is Ns

Answer 3

impulse is the integral of the resultant force (F) with respect to time:
\[J = \int\limits_{t1}^{t2}F.dt\]