Question

Calculus. Limits

Answer 1

\[a_n= \frac{ \sin (3n) }{ 4+\sqrt n }\]

Answer 2

Determine whether the sequence converges or diverges. If it converges, find the limit.

Answer 3

as \(n\to \infty\) you have \(\sqrt{n}\to \infty\) as well, so the denominator gets larger and larger

Answer 4

the numerator is stuck between -1 and 1, since sine is

Answer 5

right, ok

Answer 6

Do you see what the @satellte73 dish is saying about the limit?
c/infty->

Answer 7

I am picturing \[\frac{ -1\le \sin 3n \le 1 }{ \inf }\] in my head

Answer 8

sorry, I keep losing connection

Answer 9

im assuming that it is convergent at zero

Answer 10

yes

Answer 11

thank you