Question

Find the area of the rhombus if EL = 6.0 cm and KE = 8.5 cm. Talk me through this?

Answer 1

The area of a rhombus can be found with the formula
\[(pq)/2\]
where p and q are the lengths of the diagonals of the rhombus.

This problem would be a little easier if we were directly given the value of the diagonals, but we aren't. We're given pieces of the segments that form the diagonals.

The only other property that you need to know in order to solve this problem is that when the diagonals of a rhombus intersect, they bisect(cut in half) each other. So KE is half of the full diagonal, and EL is half of the full diagonal. That should be enough to get you going

Answer 2

\[A=\frac{1}{2} \times KM \times JL\]
\[A=\frac{JL}{2} \times KM\]
\[\frac{JL}{2}=EL=6\]\[KM=2 \times KE=2 \times 8.5=17\]\[A=\frac{JL}{2} \times KM=EL \times 2 \times KM=6 \times 17=102\]

Answer 3

Thanks guys! :)