Question

Chapter 5:Indices and Logarithms
@ganeshie8

Answer 1

\[Given~that~\log _{\sqrt{3}}9=x-\log _{\sqrt{3}}27.Find~the~value~of~x.\]

Answer 2

\[\log _{\sqrt{3}}9+\log _{\sqrt{3}}27=x\]

Answer 3

must we factorize it?

Answer 4

\[\log _{\sqrt{3}}\]

Answer 5

maybe combine using the property
\[\large \log_b (x) + \log_b (y) = \log_b(x*y)\]

Answer 6

\[\log _{\sqrt{3}}(9\times27)=x\]

Answer 7

change it to exponent form

Answer 8

\[9\times27=\sqrt{3}^{x}\]

Answer 9

\[\large \log_b M = k\]
is same as the equation
\[\large M = b^k\]

Answer 10

Excellent !

Answer 11

write both sides as powers of 3

Answer 12

\[3^2\times3^3=3^{\frac{ x }{ 2 }}\]

Answer 13

\[2+3=\frac{ x }{ 2 }\]

Answer 14

\[x=10\]

Answer 15

\[\large \color{red}{\checkmark}\]

Answer 16

good job !

Answer 17

Thnx @ganeshie8 :D

Answer 18

yw:)