Question

um i have another one @jagr2713 and @sleepyjess do you mind helping me? Last one I promise :)

Answer 1

Sure :D

Answer 2

Awesome

Answer 3

I will let @jagr2713 get this one, I have to go

Answer 4

why D:

Answer 5

ok Here it is \[1/3x +1/3 (2x-5 )=3 1/2\]

Answer 6

awww ok @sleepyjess

Answer 7

my mistake its not 31 over 2 its 3 and 1/2

Answer 8

oh there we go i was like what?

Answer 9

lol

Answer 10

and those are fractions not division problems haha

Answer 11

\[\frac{ 1 }{ 3 }x+\frac{ 1 }{ 3 }(2x-5)=3\frac{ 1 }{ 2 }\]

Answer 12

?

Answer 13

yea thats it ...how did you do that?

Answer 14

press the equations button

Answer 15

ok

Answer 16

oh i figured it out haha nvm

Answer 17

me to lol :D

Answer 18

wait figure out the question the equation thing?

Answer 19

the equation button thing

Answer 20

oh ok lets finish what were doing

Answer 21

ok

Answer 22

i have no idea what to do on this one

Answer 23

ok first we convert the mix numbers\[3\frac{ 1 }{ 3 }\] into an improper fraction first by multiplying the denominator (2) by the whole number part (3) and add the numerator (1) to get the new numerator. Place the new numerator (7) over the old denominator (2).
and we get
\[\frac{ 1 }{ 3 }x+\frac{ 1 }{ 3}(2x-5)=\frac{ 7 }{ 5 }\]

Answer 24

then we simply each term
and what do we get?

Answer 25

um i have no idea i hate fraction equations

Answer 26

so we multiply 1/3 by x to get (1/3)x
\[(\frac{ 1 }{ 3 })x+\frac{ 1 }{ 3}(2x-5)=\frac{ 7 }{ 2 }\]

Answer 27

then we simplify
\[\frac{ x }{ 3 }+\frac{ 1 }{ 3 }(2x-5)=\frac{ 7 }{ 2 }\]

Answer 28

ok what do we multiply next?

Answer 29

-_- i don't know :( um inside the () ?

Answer 30

close but we multiply 1/3 by 2x-5 to get (1/3)(2x-5)
\[\frac{ x }{ 3 }+(\frac{ 1 }{ 3 })(2x-5)=\frac{ 7 }{ 2 }\]

Answer 31

then we apply the distributive property
\[\frac{ x }{ 3 }+(\frac{ 1 }{ 3 })(2x)+(\frac{ 1 }{ 3 })(-5)=\frac{ 7 }{ 2 }\]

Answer 32

what do you think we do with 1/3 and 2x

Answer 33

make it 2 and 1 /3 x?

Answer 34

close again but we simplify to make it
\[\frac{ x }{ 3 }+\frac{ 2x }{ 3 }+(\frac{ 1 }{ 3 })(-5)=\frac{ 7 }{ 2 }\]

Answer 35

from reading that what do we do to 1/3 and -5

Answer 36

multiply

Answer 37

simplify yes and what do we get

Answer 38

um -1.67

Answer 39

now like the other one we do we get
\[\frac{ x }{ 3 }+\frac{ 2x }{ 3 }+\frac{ -5 }{ 3 }=\frac{ 7 }{ 2 }\]

Answer 40

next we move the negative in the front of the fraction, what do we get

Answer 41

x/3 + -5/3 + 2x/3 = 7/2

Answer 42

brb

Answer 43

k

Answer 44

correct but you just flip 2x/3, -5/3

Answer 45

\[\frac{ x }{ 3 }+\frac{ 2x }{ 3 }-\frac{ 5 }{ 3 }=\frac{ 7 }{ 2 }\]

Answer 46

i have to go in a min...can we kinda speed this up? not meaning to be rude

Answer 47

ok now for me i usually combine the to numerators u can if u want but i am going to combine and get
\[\frac{ x }{3 }+\frac{ 2x-5 }{ 3 }=\frac{ 7 }{ 2 }\]
the den stays the same

Answer 48

umm sure

Answer 49

:)

Answer 50

ok but u have at least 5mins

Answer 51

no maybe 2

Answer 52

2 mins that is

Answer 53

ok

Answer 54

Combine x/3+(2 x-5)/3 into a single fraction.
x/3+(2 x-5)/3 = ((2 x-5)+x)/3:
(2 x+x-5)/3 = 7/2
Group like terms in 2 x+x-5.
Grouping like terms, 2 x+x-5 = (x+2 x)-5:
((x+2 x)-5)/3 = 7/2
Add like terms in x+2 x.
x+2 x = 3 x:
(3 x-5)/3 = 7/2

Answer 55

whoa

Answer 56

u want me to go fast right?

Answer 57

yes haha

Answer 58

Multiply both sides by a constant to simplify the equation.
Multiply both sides of (3 x-5)/3 = 7/2 by 3:
(3 (3 x-5))/3 = 3×7/2
Express 3×7/2 as a single fraction.
3×7/2 = (3×7)/2:
(3 (3 x-5))/3 = (3×7)/2
Cancel common terms in the numerator and denominator of (3 (3 x-5))/3.
(3 (3 x-5))/3 = 3/3×(3 x-5) = 3 x-5:
3 x-5 = (3×7)/2
Multiply 3 and 7 together.
3×7 = 21:
3 x-5 = 21/2
Isolate terms with x to the left hand side.
Add 5 to both sides:
3 x+(5-5) = 21/2+5
Look for two terms that sum to zero.
5-5 = 0:
3 x = 21/2+5
Put the fractions in 21/2+5 over a common denominator.
Put 21/2+5 over the common denominator 2. 21/2+5 = 21/2+(2×5)/2:
3 x = 21/2+(2×5)/2
Multiply 2 and 5 together.
2×5 = 10:
3 x = 21/2+10/2
Add the fractions over a common denominator to a single fraction.
21/2+10/2 = (21+10)/2:
3 x = (21+10)/2

Answer 59

whats next?

Answer 60

wow 0.0

Answer 61

you dont get it?

Answer 62

not really

Answer 63

yea i cant do it in 2mins lol

Answer 64

well can you just give me the answer? please?

Answer 65

i cant but i am almost done :D just couple more secs

Answer 66

:( fine

Answer 67

ok now we evaluate 21+10
so we get 31
\[3x=\frac{ 31 }{ 2 }\]

Answer 68

now we solve for x

so we divide both sides by 3

\[x=\frac{ 31 }{ 2*3 }\]

Answer 69

whats the answer?

Answer 70

you there @koolkat13

Answer 71

5.16

Answer 72

no this is the easiest part what is 3*2

Answer 73

6

Answer 74

so the answer is?

Answer 75

31/6 = 5.167

Answer 76

31/6 is correct but you dont have to divide anymore b.c 31 doesnt go into 6 so leave as it is ;D

Answer 77

oh ok hehe

Answer 78

:D now you may leave

Answer 79

haha ok thx bye :D

Answer 80

bye