Question

1. A sailboat moves north for a distance of 10.00 km when blown by a wind from the exact southeast with a force of 2.00 × 104 N. The sailboat travels the distance in 1.0 h. How much work was done by the wind? What was the wind’s power? Your response should include all of your work and a free-body diagram.

For work i got 200,000 J and for the power i got 3,333.3 is that right???

Answer 1

Work is equivalent to Force times distance times the cosine of the angle of the force.

Answer 2

So for this specific problem you get W= Fdcos(45)

Answer 3

Which is (2.00 x 10^4N)(10.00 x 10^3 m)(cos45)

Answer 4

Power is work over time so put your answer over the time. What values doyou get?

Answer 5

for work this time i got 2.7 x 10 ^9 is that right @TheDream

Answer 6

No that isn't correct all you have to do for work is plug in the equation above into a calulator

Answer 7

When i do it i get 1.41 x 10^8

Answer 8

For cos45 your calculator should be in degress

Answer 9

Sorry I dont have a scientific calculator

Answer 10

Do you have windows?

Answer 11

for t would i do 60 or 1 ?

Answer 12

i do

Answer 13

Neither. There is 60 secs in a minute and 60 minutes in an hour. So you multiply the two and get 3600 seconds in 1 hour.

Answer 14

You want seconds to make sure the units match up

Answer 15

so i do 1.41 x 10 ^8 / 3600

Answer 16

Yup.

Answer 17

And there is a built in scientific calculator in Windows