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Mathematics 8 Online
OpenStudy (sparklestaraa):

The equation below shows the relationship between the temperature in degrees Celsius, C, and degrees Fahrenheit, F:

OpenStudy (sparklestaraa):

OpenStudy (anonymous):

To isolate the term containing C, subtract 32 from both sides. Can you do that?

OpenStudy (sparklestaraa):

How can i subtract 32 from f? @ospreytriple

OpenStudy (anonymous):

It becomes F-32.

OpenStudy (sparklestaraa):

f-32=9/5 c+32 -32 f-32=(9/5)c Is that correct?

OpenStudy (anonymous):

Now you should have\[F-32=\frac{ 9 }{ 5 }C\]How should you get rid of the 9/5 and isolate C?

OpenStudy (sparklestaraa):

ahhh ok :P u move 9/5 to the other side making it -9/5 correct?

OpenStudy (anonymous):

Not quite. The C is being MULTIPLIED by 9/5. What is the inverse operation of multiplication?

OpenStudy (sparklestaraa):

division :D

OpenStudy (anonymous):

Right. So you need to divide both sides by 9/5. Can you do that?

OpenStudy (sparklestaraa):

f=160/9+9/5c correct?

OpenStudy (anonymous):

Let's back up and take it in smaller steps. Instead of thinking a C as being multiplied by 9/5, we can think of C as being MULTIPLIED by 9 and DIVIDED by 5. OK?

OpenStudy (sparklestaraa):

I'm confused its a variable how do i multiply that

OpenStudy (anonymous):

I'm just trying to say that\[\frac{ 9 }{ 5 }C\]and\[\frac{ 9\times C }{ 5 }\]are the same thing. Does that make sense?

OpenStudy (anonymous):

Remember, your job is to isolate C.

OpenStudy (sparklestaraa):

ahhhhh ok so i just divide 9/5 on that one side theoretically right?

OpenStudy (sparklestaraa):

waitttttt that is just 1 and 4/5 :D

OpenStudy (anonymous):

Right. But you have to divide BOTH sides by 9/5. What do you get?

OpenStudy (anonymous):

\[\frac{ F-32 }{ \frac{ 9 }{ 5 } }=\frac{ \frac{ 9 }{ 5 }C }{ \frac{ 9 }{ 5 }}\]You're doing this. Now simplify.

OpenStudy (sparklestaraa):

so 32 divided by 9/5 is 160/9 or 17.7? so its f- 160/9 and 81c/25 ?

OpenStudy (anonymous):

What do you get when you divide any number by itself? Like 2/2=?

OpenStudy (sparklestaraa):

0 :D

OpenStudy (anonymous):

Nope. Try again.

OpenStudy (anonymous):

What is 1/1, or 2/2, or 3/3, or 1.8/1.8?

OpenStudy (anonymous):

\[F-32=\frac{9C}{5}\] Instead of diving by 9/5 all at once you can instead multiply by 5 first \[5(F-32)=\frac{5 \times9C}{5}\]

OpenStudy (anonymous):

It is much simpler to understand like this

OpenStudy (anonymous):

Thanks @Nishant_Garg . If you read above, we've looked at that.

OpenStudy (anonymous):

Yeah the next step you need to figure out @Sparklestaraa

OpenStudy (anonymous):

What do you think would happen if we multiply 9C with 5 and divide by 5 aswell, sound like knitting a sweater and tearing it back apart!

OpenStudy (anonymous):

Right now we're struggling with 5/5. Any additional insight you can provide are appreciated.

OpenStudy (anonymous):

Sorry folks, I have to leave. Good luck @Sparklestaraa.

OpenStudy (anonymous):

are you there @sparklesstaraa

OpenStudy (anonymous):

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