Question

Joan’s washing machine tub is a cylinder with a height of 17 in. and a diameter of 22 in. Her washer was half full of water when it stopped working. The repair person’s pump removed 46.2 in3 of water every second.

How many seconds did it take to empty the washer? Use 3.14 to approximate pi, and round your answer to the nearest whole number.

Answer 1

Use the volume for a cylinder V=pi*r^2*h. Divide by 2 since it is half full. Then take that answer and divide it by the amount of water the pump removes per second

Answer 2

don't forget r= diameter/2

Answer 3

598.35

Answer 4

If volume of a cylinder is defined as: \(V = \pi r^2 h\),
Because they've given you diameter, you want to find the radius as the diameter / 2 : \(r = \dfrac{D}{2}\)
then removing water has to be with the time, you want to divide how much volume in contained within the washer itself up to the time it's stopped working, which would be \(V_{\sf half ~full} = \pi r^2 h_1\)

You're given \(h=17 ~in~,~ r=\dfrac{D}{2} = \dfrac{22~ in}{2} = 11~ in\) , Adn so you can use this to find \(V_{\sf half~ full}\)

Then to find out how much TIME, make a ratio: \(\dfrac{V_{\sf half~full}}{V_{\sf rate}}\)_

Answer 5

\[\frac{V_{\sf half~full} ~in^3}{V_{\sf rate} ~\dfrac{in^3}{s}} = ~? ~ s \]

Answer 6

Nope.

Answer 7

Find your \(V_{\sf half~full}\) and tell me what you get using \(\pi = 3.14\).

Answer 8

what's the Vhalf full

Answer 9

Vhalf full should be volume of the entire washing machine divided by two

Answer 10

soooooooooo

Answer 11

93.5

Answer 12

V=(3.14)*(11)^2*(17)=?

Answer 13

3485.98

Answer 14

6485.98 sorry type-o

Answer 15

Great that is that volume, since it is half full you divide that by 2

Answer 16

Now you have 3229.49 in^3 * 1/46.2 seconds/in^3 = The inches should cancel out and you are left with your answer in seconds

Answer 17

Precisely.

Answer 18

i don't know the answer

Answer 19

can't figure it out

Answer 20

just tell me the answer

Answer 21

Sorry,I cant do that.

Answer 22

it only lets me type 2 numbers

Answer 23

If you read the problem its says round to the nearest second

Answer 24

69

Answer 25

or 70

Answer 26

Solve: \[\sf 3229.49~~ in^3 \cdot \frac{1~s}{46.2 ~in^3}\]

Answer 27

What is the rule for rounding. 5-9 round up and for 0-4 round down.

Answer 28

69.91 rounded up is 70

Answer 29

Yep.

Answer 30

70 is the answer, really

Answer 31

u both were wrong! it was 7

Answer 32

70