Mathematics
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OpenStudy (anonymous):
If AD = 2/3AB , what is the ratio of the length of (arc) BC to the length of (arc) DE ?
1/6
1/4
2/3
3/2
3/4
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OpenStudy (anonymous):
OpenStudy (anonymous):
@pooja195
OpenStudy (anonymous):
I think it's c
OpenStudy (anonymous):
@Hero
OpenStudy (michele_laino):
Please note that, we have, by definition:
\[\begin{gathered}
arc(DE) = \overleftrightarrow {AD} \cdot 2.36 \hfill \\
arc(BC) = \overleftrightarrow {AB} \cdot 1.18 \hfill \\
\end{gathered} \]
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OpenStudy (anonymous):
Okay, so how do i find the ratio?
OpenStudy (michele_laino):
please set AD = (2/3) AB into the first expression
OpenStudy (michele_laino):
you should get this:
\[\begin{gathered}
arc(BC) = \overleftrightarrow {AB} \cdot 1.18 \hfill \\
arc(DE) = \frac{2}{3}\overleftrightarrow {AB} \cdot 2.36 \hfill \\
\end{gathered} \]
OpenStudy (anonymous):
I'm confused now
OpenStudy (michele_laino):
why?
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OpenStudy (anonymous):
I don't really understand why you do that
OpenStudy (michele_laino):
let's suppose that AB = 5 feet, what is AD?
OpenStudy (anonymous):
3?
OpenStudy (michele_laino):
Sorry I repeat my reasoning.
Let's suppose AB= 6 feet what is the length of the arc BC?
OpenStudy (michele_laino):
hint:
arc(BC)= AB * 1.18= ...?
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OpenStudy (anonymous):
7.08?
OpenStudy (michele_laino):
ok!
and what is the length of the segment AD?
OpenStudy (michele_laino):
Hint: AD = 2/3* AB= 2/3 * 6=...?
OpenStudy (anonymous):
4?
OpenStudy (michele_laino):
ok!
and what is the length of the arc DE?
hint:
arc(DE) = AD * 2.36=...?
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OpenStudy (anonymous):
14.16?
OpenStudy (michele_laino):
I think 4*2.36= 9.44
OpenStudy (anonymous):
Ohhh sorry i got my numbers mixed up >.<
OpenStudy (michele_laino):
ok! now we know that
arc(BC) = 7.08
and
arc(DE) = 9.44
so what is the ratio:
arc(BC)/ arc(DE) =...?
OpenStudy (anonymous):
3/4 ?
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OpenStudy (michele_laino):
that's right!
OpenStudy (anonymous):
Is that the answer?
OpenStudy (anonymous):
@Michele_Laino ?
OpenStudy (michele_laino):
yes!
OpenStudy (anonymous):
Okay thank you so much for the help :)
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OpenStudy (michele_laino):
thank you!