medals+fan 1)set up the equations that would allow you to solve for x and y, solve once set up. give your answers in simplest radical form 2)set up the equations that would allow you to solve for a and b, solve once set up. give your answers in simplest radical form
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For a, since we have two unknowns we need two equations. Since it is a right triangle, can we relate x, y, and 5 together? How about x, 30, and 5?
do you know the trigonometric ratios?
for number 2|dw:1424130758946:dw|
and no I never learned it
Im really confused
Have you learned Pythagorean theorem? if so, that will give us 1 equation.
um yes I think so a2+b2=c2 or was it minus
that right c^2 is the longest side( the hypotenuse)
Correct, so for the first triangle, where would we put x? how about y? how about 5?
I drew a picture @kmeis002 and that means the longest side is y?
That is correct, so that would go into \(c^2\): \[a^2 + b^2 = y^2 \] So a =x and b = 5 (or vice versa) \[x^2 + 25 = y^2 \]
Now we just need to learn the definitions of \(\sin(x), \cos(x), \tan(x)\)
OKay. I think I got that one
We need one more equation, but notice that the definition of the functions above are: \[\sin(\theta) = \frac{b}{c} \\ \cos(\theta) = \frac{a}{c}\\ \tan(\theta) = \frac{b}{a} \] For the triangle pc|dw:1424144024479:dw|
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