a central pivot irrigation system is watering a circular field with radius 120 feet. The system rotates pi/3 radians in one hour. what area(to the nearest square foot) is watered in one hour?

Question

anonymous · Answer

help plsss

jim_thompson5910 · Answer

ignore the pi/3 radian angle for now

jim_thompson5910 · Answer

what is the area of the entire circle (radius = 120 ft) ?

anonymous · Answer

pir squred

jim_thompson5910 · Answer

pi*r^2, yes

now plug in r = 120 and you get what?

anonymous · Answer

45238.9

jim_thompson5910 · Answer

that's the approximate area, yes

jim_thompson5910 · Answer

there are 2pi radians in a full revolution

but we only water pi/3 radians in one hour

divide the two values:

pi/3 divided by 2pi = (pi/3)*(1/(2pi)) = pi/(6pi) = 1/6

this shows us that in one hour, we have watered 1/6th of the entire circle

jim_thompson5910 · Answer

so you have to take 1/6 of the area, or divide the area by 6, to get your final answer

don't forget to round to the nearest square foot when you're all done

anonymous · Answer

thank you soo much <3333

jim_thompson5910 · Answer

no problem