Question

Please help, will medal and fan

\[\frac{ 1 }{ b+1 }+\frac{ 1 }{ b-1 }=\frac{ 2 }{ b ^{2} -1 }\]

Answer 1

Solve for b

Answer 2

first find common denominator left side

Answer 3

(b+1)(b-1) ?

Answer 4

\[\frac{ (b-1)+(b+1) }{ (b-1)(b+1) }=\frac{ 2 }{ b ^{2} -1 }\]

Answer 5

tag meh :P

Answer 6

is that right? @Nnesha

Answer 7

thanks for tagging i'm not getting not notification :)

Answer 8

yes that is right

Answer 9

now factor denominator of right side

Answer 10

remember difference of square we did yesterday

Answer 11

\[\frac{1}{b+1}+\frac{1}{b-1}=\frac{b+1}{(b+1)(b-1)}+\frac{b-1}{(b+1)(b-1)}=\frac{b}{b^2-1}\]

Answer 12

\[\frac{b}{b^2-1}=\frac{2}{b^2-1}\]

Answer 13

wait, @Nnesha did I do it wrong? look at idku's

Answer 14

this is right now combine like terms at the numerator