if h(x)=g(x)(f(x)+1), where f(2)=-3, g(2)=4, f'(2)=-2, and g'(2)=7, find h'(2).
this is what i have:
h'(2)=g'(2)(f(2)+1)+(f(2)+1)'g(2)
h'(2)=7(-3+1)+(-2)4
h'(2)=-22
is this right?

Question

if h(x)=g(x)(f(x)+1), where f(2)=-3, g(2)=4, f'(2)=-2, and g'(2)=7, find h'(2). 
this is what i have:
h'(2)=g'(2)(f(2)+1)+(f(2)+1)'g(2)
h'(2)=7(-3+1)+(-2)4
h'(2)=-22
is this right?

anonymous · Answer

i say yes your right

anonymous · Answer

how sure are you?

thesmartone · Answer

Yes there is @NH4C But you can just post in the main Math area :)

jhannybean · Answer

For specific calculus - related problems, post in the calculus section. Then you will get help from people who know how to solve calculus-based problems and faster solutions than people who only take stabs at the problem.

unklerhaukus · Answer

h(x) = g(x)(f(x)+1)
h(2) = g(2)(f(2)+1)

h'(2) = g'(2)(f(2)+1)+(f(2)+1)'g(2)
h'(2) = 7(-3+1)+(-2)'4
h'(2) = 7(-2)+0(4)                derivative of a constant is zero 
h'(2) = -14