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find the invers of the one-to-one function f(x)=4/5x-1
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answer key says it is f^-1(x)=4/5x+1/5
\[y=\frac{4}{5x-1}\]\[x=\frac{4}{5y-1}\]\[x(5y-1)=4\]\[5y-1=\frac{4}{x}\]\[5y=\frac{4}{x}+1\]\[5y=\frac{4}{x}+\frac{x}{x}\]\[5y=\frac{4+x}{x}\]\[y=\frac{4+x}{5x}\]
\[f^{-1}(x)=\frac{x+4}{5x}\]
answer key says4/5x+1/5 ????
is the answer key wrong ?????????????????????????????????????????????????
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I also got 4+x/5x
this is my test review im calm im just thinking maybe the teacher did a typo my answer key to this problem is 4/5x +1/5
Note that: \[ \frac{4}{5x} + |\frac{1}{5} = \frac{4}{5x} + \frac{x}{5x} = \frac{4+x}{5x} = \frac{x+4}{5x}\] Note that these answers are the same, just in different form
I see that thanks
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