Question

Could I get some help with this? Solve √x=4 for x

Answer 1

there is square root of x
to cancel out square root you have to take square both side

Answer 2

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Answer 3

\[\huge\rm \sqrt{x} = x^\frac{ 1 }{ 2 }\]
so when u take square root square root cancel out

Answer 4

Would my answer be 4?

Answer 5

Is your question?

\(\Large\sqrt{x}=4\)

Answer 6

You have first square each side of the equation. When you do that, you'll get x = 16 as your final answer. Hope that helps!

Answer 7

nope take square both side

Answer 8

Yes

Answer 9

The square root so 16 is 4, so 4?

Answer 10

not square root
take square

Answer 11

Or 16?

Answer 12

what is \[\huge\rm (\sqrt{x})^2\] = ????

Answer 13

I'm not sure how I do that

Answer 14

remember that \(\LARGE\sqrt{x}=x^\frac{1}{2}\)

Answer 15

like i said before square root of x can be written as 1/2 exponent
so what is \[\huge\rm (x^{\frac{ 1 }{ 2 }})^2\]