Question

HELP ME
(1/a+1)(1/b+1)(1/c+1)=1
and P=a^2+b^2+c^2

Answer 1

what are the directions for the problem

Answer 2

You want to find the value of a^2 + b^2 + c^2 ?

Answer 3

@freckles interesting the question is a month old

Answer 4

but I see @Hackerpham5 here
like he did bump and he is here
so maybe he will still say something

Answer 5

he gave me medal

Answer 6

maybe your guess was right then

Answer 7

maybe the directions say "find P =a^2 + b^2 + c^2"

Answer 8

http://openstudy.com/users/hackerpham5#/updates/54e2ab86e4b0db7d6b0f5288
look there looks like there is a little more here?

Answer 9

I don't know what all that other stuff means though .

Answer 10

might be a small language barrier

Answer 11

find the min

Answer 12

for a,b,c of (0;1) and (1/a+1)(1/b+1)(1/c+1)=1
find the min P=a^2+b^2+c^2
is what that translates to

Answer 13

We can try to do lagrange multipliers maybe