Question

General Solution

Answer 1

\[\csc y dx + \sec x dy = 0\]

Answer 2

Ok I just solved this though :\

Answer 3

If the format is, as @UsukiDoll says, then h(y)dy = f(x)dx

Answer 4

hi I'm back!

Answer 5

let's try get it in dy/dx = blank form

Answer 6

\[secx dy = cscy dx\]

Answer 7

then all of my y's should be on the left and all of my x's on the right

Answer 8

Soo.... \[\csc(y)dx = -\sec(x)dy\]\[\frac{\csc(y)}{dy} = -\frac{\sec(x)}{dx}\]\[\int \sin(y)dy = -\int \cos(x)dx\]\[-\cos(y) = \sin(x)+C\]But what happens now? O_o

Answer 9

\[\frac{dy}{cscy}=\frac{dx}{secx}\]

Answer 10

huh rule of thumb.. never have dy and dx's on the bottom. always on the top!

Answer 11

Ooo, ok.

Answer 12

I am learning!!!

Answer 13

that's ok ^_^

Answer 14

starting over from step 2

Answer 15

so we just need to know what