Question

WORKING WITH ELIPSES PLEASE HELP… WILL FAN AND MEDAL

Answer 1

What is the length of the minor axis of the following graph?

http://static.k12.com/eli/bb/815/-1/0/2_36683_44255/-1/1c862a0648b77ac494c897d10ee98f0e6fcac9d8/media/2361664f8076cb4455c8762178dc1a82b125423b/mediaasset_672014_1.gif

Answer 2

@Kainui ?? do u think u can help with this

Answer 3

@@iGreen. @Michele_Laino or either of you two?

Answer 4

@iGreen.

Answer 5

please note that the minor axis is the vertical axis

Answer 6

i found my answer to be 3…. but now I'm stuck on how to find the foci of ellipses.

Answer 7

http://static.k12.com/eli/bb/815/-1/0/2_36683_44255/-1/1c862a0648b77ac494c897d10ee98f0e6fcac9d8/media/9b8a4bd356f88e10229a9c6a4c7e6aa04a22f25f/mediaasset_672006_1.gif this is my graph… but I'm not given any information.

Answer 8

note that the equation of your ellipse is:
\[\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{9} = 1\]

Answer 9

whereas the equation of your second ellipse, is:
\[\frac{{{x^2}}}{9} + \frac{{{y^2}}}{{25}} = 1\]

Answer 10

how do you find x and y I'm just completely confused

Answer 11

i just don't know how to find the foci of the second link i sent.. theres about 4 questions all based on foci but idk how to do it

Answer 12

in order to find the x-coordinates of the foci, you have to apply this formula:
\[{a^2} - {c^2} = {b^2}\]
where a= 3 and b=5

Answer 13

i got -4i and 4i

Answer 14

sorry I have made an error:
a= 5 and b=3

Answer 15

so then -4 and 4

Answer 16

\[\begin{gathered}
{c^2} = {a^2} - {b^2} = 25 - 9 = 16 \hfill \\
c = \pm 4 \hfill \\
\end{gathered} \]

Answer 17

so now i plug x (4) into the equation and solve for y?

Answer 18

ok! your foci are:
\[\begin{gathered}
{F_1} = \left( {0,4} \right) \hfill \\
{F_2} = \left( {0, - 4} \right) \hfill \\
\end{gathered} \]

Answer 19

but thats not in my answer choices:(

Answer 20

I'm sorry the right value of a is 6

Answer 21

so then (0,6) and (0,-6) ?

Answer 22

can you tell me how you got a and b?

Answer 23

so
c^2 = 36-9=27
and your foci are:
\[\begin{gathered}
c = \pm 3\sqrt 3 \hfill \\
{F_1} = \left( {0,3\sqrt 3 } \right) \hfill \\
{F_2} = \left( {0, - 3\sqrt 3 } \right) \hfill \\
\end{gathered} \]

Answer 24

thats still not in my answer choices :(( which graph are u working on?

Answer 25

please can you post again your graph?

Answer 26

http://static.k12.com/eli/bb/815/-1/0/2_36683_44255/-1/1c862a0648b77ac494c897d10ee98f0e6fcac9d8/media/9b8a4bd356f88e10229a9c6a4c7e6aa04a22f25f/mediaasset_672006_1.gif

Answer 27

please what are your options?

Answer 28

\[(0,-6) (0,6) \]

Answer 29

\[(0,-\sqrt{27}), (0,\sqrt{27})\]

Answer 30

\[(-3,0) (3,0)\]

Answer 31

\[(-6,0) (6,0)\]

Answer 32

yes! please note that sqrt(27) = 3*sqrt(3)

Answer 33

the vertices of your ellipse are:
\[\begin{gathered}
\left( {0,6} \right) \hfill \\
\left( {0, - 6} \right) \hfill \\
\end{gathered} \]

Answer 34

and:
\[\begin{gathered}
\left( {3,0} \right) \hfill \\
\left( { - 3,0} \right) \hfill \\
\end{gathered} \]

Answer 35

so my foci is..?

Answer 36

your foci are:
\[\begin{gathered}
{F_1} = \left( {0,3\sqrt 3 } \right) = \left( {0,\sqrt {27} } \right) \hfill \\
{F_2} = \left( {0, - 3\sqrt 3 } \right) = \left( {0, - \sqrt {27} } \right) \hfill \\
\end{gathered} \]

Answer 37

thank you!

Answer 38

Thank you!