CHECK MY ANSWER!!! I THINK IT'S OPTION A Tiffany kicks a soccer ball off the ground and in the air, with an initial velocity of 28 feet per second. Using the formula H(t) = -16t2 + vt + s, what is the maximum height the soccer ball reaches? 15.6 feet 14.1 feet 13.5 feet 12.3 feet
that "s" represents the INITIAL HEIGHT of the soccer ball. Obviously it's not going to be a very large number, since most of us could not kick a soccer ball that was more than about 5 feet in the air, right? If v = initial velocity = 28 (ft/sec), then your equation becomes APPROXIMATELY H(t) = -16*t^2+28t+5. Note that you didn't include the t^2 earlier, so I've fixed that. Now, if you'd graph H(t) = -16*t^2+28t+5, you could see pretty easily what the maximum height will be. Sound OK?
15.6
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