A force of magnitude 44N compresses a spring 0.69m from equilibrium. What is the value of the spring constant?

Question

A force of magnitude 44N  compresses a spring 0.69m  from equilibrium. What is the value of the spring constant?

anonymous · Answer

Hi Loza...
To answer this question, you get to use Hooke's Law! yay

Hooke's Law is F=-Kx
F is obviously the force applied to a spring.
The stuff on the other side of the = sign is negative because it is obeying Newton's 3rd law of opposite and equal reactions.

The K is called the spring constant and is different for every spring.

The x is simply the distance the spring is either compressed or stretched.

In you question:
A force of magnitude 44N compresses a spring 0.69m from equilibrium. What is the value of the spring constant?

F=44 N
K=???
x=0.69m

Since everything is in standard SI units, just algebraically rearrange the equation to solve for K!

So F=-Kx becomes
-F/x = K

Just do the math and don't forget your units...
You should get something like -44N/0.69m=63.768N/m
If you are wondering why the answer is not negative, it's because the spring constant is a magnitude, so it's positive!

Hope this helps! :o)

anonymous · Answer

@Loza14

anonymous · Answer

Hey, can you come and check my question? @SinginDaCalc2Blues

anonymous · Answer

send me the link and I will look

anonymous · Answer

Thanks!