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OpenStudy (anonymous):
help..
http://static.k12.com/bank_packages/files/media/mathml_8c85eee488c0d22e6533e4c1e7991d4f76867dd8_1.gif
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OpenStudy (adamk):
\[b ^{-4}\] is the same as \[\frac{ 1 }{ b^4 }\]
OpenStudy (samara8954):
what grade you in I'm in k12 7th grade
OpenStudy (anonymous):
\[b^{-4}=\frac{1}{81}\\b^{-4}=3^{-4}\\b=3\]
OpenStudy (anonymous):
ok..
OpenStudy (anonymous):
@Samara8954 k12 too. but i am in 8th grade
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OpenStudy (adamk):
x = -3 and x = 3
Take the reciprocal of both sides of 1/b^-4 and 1/81 to get:
b^4 = 81
Then you can simply to x^2 = 9 and x^2 = -9
OpenStudy (adamk):
simplify*
OpenStudy (anonymous):
im honestly still confused @AdamK
OpenStudy (adamk):
I know. Sorry. Basically, the equation reduces to b^4 = 81. Then, you take the cube root of 81 which is 3 or -3.
OpenStudy (anonymous):
3?
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OpenStudy (adamk):
Sorry. I didn't mean to say "or". It's 3 AND -3. Both numbers are answers. Because 3 * 3 * 3 * 3 = 81 and -3 * -3 * -3 * -3 = 81.
OpenStudy (anonymous):
so its either one? i can choose either one and it would be correct?
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