Question

LAST QUESTION
What is the slope-intercept form of the function that contains the point (1, –2) and has a slope of –3?

Answer 1

start by plugging the information into the point-slope form equation \(y-y_1=m(x-x_!)\) where \((x_1,y_2)\) is the point the line goes through and m is the slope of the line, then solve for y

Answer 2

x1,y1*

Answer 3

idk

Answer 4

what does that mean? read what I said.

\(y-\color{green}{y_1}=\color{blue}m(x-\color{red}{x_1})\)

\((\color{red}{1}, \color{green}{–2}) \)

\( slope = \color{blue}{–3}\)

Answer 5

refresh to see the negatives

Answer 6

y-(-2)=-3(x-1)

Answer 7

it needs to be in y=mx+b form

Answer 8

correct. so simplify the left side. y-(-2)=y+2
then distribute the -3

Answer 9

that's why I said solve for y

Answer 10

oh ok

Answer 11

y+2= -3x - -3

Answer 12

yep

Answer 13

ok now what

Answer 14

solve for y? that means isolate y. get it a lone

Answer 15

how do i do that

Answer 16

the same way you'd solve y+2=45

Answer 17

i dont know how to isolate y

Answer 18

how would you do it in the "y+2=45"

Answer 19

divide 2 by 45?

Answer 20

can i add the 2 to b?

Answer 21

subtract 2. addition and subtraction are inverse operations

Answer 22

if you add something and then subtract the same thing, you end up with the same thing

Answer 23

x+4-4=x

Answer 24

so y= -3x + 1 ?

Answer 25

y-(-2)=-3(x-1)

y+2=-3x--3
y+2=-3x+3
y=-3x+1

yeah, good job

Answer 26

another way of doing this is using y=mx+b where m is the slope and b is the y intercept

Answer 27

the y intercept is where x=0, so you'd have to find (0,y) first
since the slope is -3, if we go back one x unit, we'd subtract -3 from the y
(1, –2)
(0, 1)

and so we have y=-3x+1

Answer 28

god dammit I hate this site