Question

I am stuck help!!!!

2-(4/x^2) =2/x

2=2/x+4x^2

I then got

2=2x/x^2 + 4/x^2

2= 2x+4/x^2

What to do next

I dont know what to do with the x^2

Answer 1

\[2-\frac{ 4 }{ x ^{2} }=\frac{ 2 }{ x }\]

Is that the original problem?

Answer 2

Yes

Answer 3

It would be easiest if you find a common denominator first. Then you can multiply each term by the common denominator and clear all the fractions.

Answer 4

X^2 IS the common deniminator

Answer 5

Correct. So multiply each of the terms by x^2, then that will clear your denominators.

Answer 6

I don't know how to do that. I get what u mean but if how to set it up

Answer 7

2 times x^2 = 2x^2
4/x^2 times x^2 will cancel the x^2 and just = 4
2/x times x^2 will cancel one x so = 2x

So you'd have
\[2x^{2}-4=2x\]

Answer 8

Do I just factor now

Answer 9

Get all terms on one side, then factor. Yep!

Answer 10

OK so it would be 2 (x+1)(x-2)