Question

Please help! Medal + Fan! :)

Answer 1

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Answer 2

Evaluate each logarithm;
(a). \[Log _{3} \frac{ 1 }{ 9 }\]
(b). \[\log _{2}1\]

Answer 3

We've done this in class, and I normally know this, but today I'm not feeling good and I just don't remember how to do it. :(

Answer 4

Can you write 1/9 as a power of 3?

Answer 5

What do you mean?

Answer 6

Well, how about 9? Can you write 9 as a power of 3, i.e. 3 raised to an exponent?

Answer 7

Ohhh wait, I remember what to do.

Answer 8

The way my teacher taught it, she said to do log 1/9 divided by log 3

Answer 9

Not sure what your teacher means by that. I assume you realize that 9 is 3^2. Right?

Answer 10

Yeah, I know that. But for the notes, she said to do:
\[\log \frac{ 1 }{ 9 }\div \log 3\] and you would get a decimal which is what she wants. I guess

Answer 11

Shouldn't be a decimal. Log is just a fancy way of simplifying exponents.

For those 2 questions, you need to put them back into exponential form.

Answer 12

Fair enough. Plug it in your calculator. But there's no decimal in this answer. It's a nice integer answer.

Answer 13

The way my teacher taught it, she made up divide it and get a decimal

Answer 14

When you see a question like this, try to write the argument as a power of the index of the logarithm.

Answer 15

us*

Answer 16

\[\log_{3}\frac{ 1 }{ 9 } \]
My way of putting log into exponential form or vice versa is using the form "B.A.E"

Base, Answer, Exponent

Base:3
Answer:x
Exponent:1/9

3^x=1/9

Evaluate x.

Answer 17

OK. You taking over @dtan5457 ?

Answer 18

No, you can stay. I'm just giving my insight.

Answer 19

It's fine I got my answer

Answer 20

Thank you though :)